lix
Channel@sanlixus
Кмм закрытыПо вопросам - @yatogtimlАнонимка - t.me/anonaskbot?start=nWRUoGxMPNA0ATJ
Measured performance snapshot
Only crawler-observed values are shown. Missing history stays missing instead of becoming zero.
- Members
- 5,660 At last successful crawl
- Average post views
- 2,841 Sampled public posts
- Sampled ERR
- 50.19% Average views ÷ members
- 7-day growth
- Not enough data Complete 7-day baseline required
- 30-day growth
- Not enough data Complete 30-day baseline required
- 90-day growth
- Not enough data Complete 90-day baseline required
Member growth
The growth chart appears once our crawler has recorded at least two member checkpoints for this channel. Fresh listings fill in within a few days.
Data quality passport
Freshness: stale · Classification: automatic · Confidence: 42%
Audience authenticity, audience country and Telegram Ads approval are not verified. Sampled views are not normalized by post age and are not a guarantee of engagement.
Inventory limits: non ad topic; low classification confidence; outside internal inventory; stale profile.
Save or compare this channelClaim or correct this profileAbout this channel
Кмм закрытыПо вопросам - @yatogtimlАнонимка - t.me/anonaskbot?start=nWRUoGxMPNA0ATJ
Recent posts
Public feed sample. Captured: 2026-09-07T13:31:59.065260. This is not a live feed.
29 ноября встретимся с вами на Фиче в мск!
🗡️
Улетела в горы ловить дзен, меня не ищите
Немного поздний подарок для Oki ✨
⚕️
Frequently asked questions
How many members does lix have?
As of our latest crawl on 2026-09-05, the channel reports about 5,660 members. The count refreshes automatically every time we re-check the profile.
How do I join lix on Telegram?
Tap “Open in Telegram” above — it opens the official t.me page for @sanlixus, where you can press Join inside Telegram.
Is joining lix free?
Yes. Public Telegram channels are free to join; only your normal internet data usage applies.
What content does it publish?
The owner describes it as: “Кмм закрытыПо вопросам - @yatogtimlАнонимка - t.me/anonaskbot?start=nWRUoGxMPNA0ATJ”